Question

Answer 1

a) Ta có: \(A=\dfrac{x^2-16}{3\left(x-4\right)}+\dfrac{x-4\sqrt{x}+4}{\sqrt{x}-2}-\dfrac{x-4}{\sqrt{x}+2}\)

\(=\dfrac{x+4}{3}+\sqrt{x}-2-\left(\sqrt{x}-2\right)\)

\(=\dfrac{x+4}{3}\)

Answer 2

ĐK : \(x\ge0;x\ne4\)

\(=\dfrac{x+4}{3}+\sqrt{x}-2-\sqrt{x}+2=\dfrac{x+4}{3}\)