Question

rút gon B=2/√x+1+√x-15/25-x

 

Answer 1

Sửa đề: \(B=\dfrac{2}{\sqrt{x}+5}-\dfrac{\sqrt{x}-15}{x-25}\)

\(=\dfrac{2\sqrt{x}-10-\sqrt{x}+15}{\left(\sqrt{x}+5\right)\left(\sqrt{x}-5\right)}\)

\(=\dfrac{1}{\sqrt{x}-5}\)

Answer 2

\(B=\dfrac{2}{\sqrt{x}+1}+\dfrac{\sqrt{x}-15}{25-x}\left(x\ge0;x\ne25\right)\\ B=\dfrac{2\left(25-x\right)+\left(\sqrt{x}-15\right)\left(\sqrt{x}+1\right)}{\left(\sqrt{x}+1\right)\left(25-x\right)}\\ B=\dfrac{50-2x+x-14\sqrt{x}-15}{\left(\sqrt{x}+1\right)\left(25-x\right)}\\ B=\dfrac{-x-14\sqrt{x}+35}{\left(\sqrt{x}+1\right)\left(25-x\right)}\)