ĐKXĐ: \(x\ne-2;y>=9\)
\(\left\{{}\begin{matrix}\dfrac{3}{x+2}+\sqrt{y-9}=5\\\dfrac{2}{x+2}+3\sqrt{y-9}=-4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{9}{x+2}+3\sqrt{y-9}=15\\\dfrac{2}{x+2}+3\sqrt{y-9}=-4\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\dfrac{7}{x+2}=15+4=19\\\dfrac{3}{x+2}+\sqrt{y-9}=5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x+2=\dfrac{7}{19}\\\sqrt{y-9}=5-3:\dfrac{7}{19}=5-3\cdot\dfrac{19}{7}=-\dfrac{22}{7}\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x=\dfrac{7}{19}-2=\dfrac{-31}{19}\\y\in\varnothing\end{matrix}\right.\)
vậy: Hệ vô nghiệm