ĐKXĐ: x<>1 và y>2
\(\left\{{}\begin{matrix}\dfrac{1}{\left|x-1\right|}+\dfrac{3}{\sqrt{y-2}}=4\\\dfrac{5}{\left|x-1\right|}-\dfrac{2}{\sqrt{y-2}}=3\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\dfrac{5}{\left|x-1\right|}+\dfrac{15}{\sqrt{y-2}}=20\\\dfrac{5}{\left|x-1\right|}-\dfrac{2}{\sqrt{y-2}}=3\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\dfrac{17}{\sqrt{y-2}}=17\\\dfrac{5}{\left|x-1\right|}=3+\dfrac{2}{\sqrt{y-2}}\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\sqrt{y-2}=1\\\dfrac{5}{\left|x-1\right|}=3+2=5\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y-2=1\\\left|x-1\right|=1\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=3\\x-1\in\left\{1;-1\right\}\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=3\\x\in\left\{2;0\right\}\end{matrix}\right.\left(nhận\right)\)
