\(\overrightarrow{AB}=\left(-4;4\right)\)
\(\overrightarrow{BC}=\left(-3;-8\right)\Rightarrow-2\overrightarrow{BC}=\left(6;16\right)\)
\(\overrightarrow{AC}=\left(-7;-4\right)\Rightarrow3\overrightarrow{AC}=\left(-21;-12\right)\)
=> \(\overrightarrow{y}=\widehat{AB}-2\widehat{BC}+3\widehat{AC}=\left(-19;8\right)\)