a) 0,25=(0,5)2; \(\dfrac{8}{125}=\left(\dfrac{2}{5}\right)^3\)
\(-\dfrac{27}{125}=\left(-\dfrac{3}{5}\right)^3\); \(\dfrac{121}{169}=\left(\dfrac{11}{13}\right)^2\)
b) \(\left(\dfrac{1}{4}\right)^3=\left[\left(\dfrac{1}{2}\right)^2\right]^3=\left(\dfrac{1}{2}\right)^6\);
\(\left(\dfrac{1}{8}\right)^5=\left[\left(\dfrac{1}{2}\right)^3\right]^5=\left(\dfrac{1}{2}\right)^{15}\)
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\(a\)) \(\text{0,25 = }\left(\dfrac{1}{2}\right)^2\) \(;\) \(\dfrac{\text{8}}{\text{125}}=\left(\dfrac{2}{5}\right)^3\)\(;\) \(\dfrac{\text{-27}}{\text{1}\text{12}}=\left(\dfrac{-3}{5}\right)^3\) \(;\) \(\dfrac{\text{121}}{\text{169}}=\left(\dfrac{11}{13}\right)^2\)
\(b\)) \(\text{1/2 = (1/2)^1}\) \(;\) \(\text{(1/4)^3 = 1/64 = (1/4)^6}\) \(;\) \(\text{(1/8)^5 = 1/32768 = (1/8)^15}\)