\(cos\left(\overrightarrow{AB};\overrightarrow{BC}\right)=-cos\widehat{ABC}=-\frac{AB^2+AD^2-AC^2}{2AB.AD}=\frac{11}{80}\)
\(\Rightarrow\overrightarrow{AB}.\overrightarrow{BC}=AB.BC.cos\left(\overrightarrow{AB};\overrightarrow{BC}\right)=5.8.\frac{11}{80}=\frac{11}{2}\)