\(\sin^2\alpha+\cos^2\alpha=1\Leftrightarrow\sin\alpha=\sqrt{1-\cos^2\alpha}=\sqrt{1-\frac{1}{3}}=\frac{\sqrt{6}}{3}\)
\(\tan\alpha=\frac{\sin\alpha}{\cos\alpha}=\frac{\frac{\sqrt{6}}{3}}{\frac{1}{\sqrt{3}}}=\sqrt{2}\)
\(\cot\alpha=\frac{1}{\sqrt{2}}\)