Để giới hạn đã cho hữu hạn \(\Rightarrow a=-2\)
\(\lim\limits_{x\rightarrow+\infty}\left(\sqrt{4x^2+8x-1}-\left(2x+b\right)\right)=\lim\limits_{x\rightarrow}\dfrac{4x^2+8x-1-\left(4x^2+4bx+b^2\right)}{\sqrt{4x^2+8x-1}+2x+b}\)
\(=\lim\limits_{x\rightarrow}\dfrac{\left(8-4b\right)x-1-b^2}{\sqrt{4x^2+8x-1}+2x+b}=\dfrac{8-4b}{4}=2-b=3\)
\(\Rightarrow b=-1\)