\(\dfrac{8}{11}+\dfrac{8}{33}\times\dfrac{3}{4}=\dfrac{8}{11}+\dfrac{2}{11}=\dfrac{8+2}{11}=\dfrac{10}{11}\)
\(\dfrac{8}{11}+\dfrac{4.2}{11.3}.\dfrac{3}{4}=\dfrac{8}{11}+\dfrac{2}{11}=\dfrac{10}{11}\)
`8/11 + 8/33 xx 3/4 = 8/11 + 2/11 = 10/11`
`8/11+8/33xx3/4=8/11+[4xx2xx3]/[11xx3xx4]=8/11+2/11=10/11`
\(\dfrac{8}{11}+\dfrac{8}{33}\times\dfrac{3}{4}=\dfrac{8}{11}+\dfrac{2}{11}=\dfrac{10}{11}\)