a \(\dfrac{24}{56}+\dfrac{63}{56}=\dfrac{87}{56}\)
b \(\dfrac{12}{15}-\dfrac{2}{15}=\dfrac{10}{15}=\dfrac{2}{3}\)
c \(\dfrac{8}{11}\times\dfrac{33}{5}=\dfrac{24}{5}\)
d \(4:\dfrac{1}{7}=4\times7=28\)
a) \(\dfrac{87}{56}\)
b) \(\dfrac{2}{3}\)
c) \(\dfrac{24}{5}\)
d) 28
a/=24/56+63/56
=87/56=2/3
b/=13/15+(-2)/15
=11/15
c/=264/55
=24/5
d/=4x7/1=28