\(\left\{{}\begin{matrix}3x-2y=-4\\4x-3y=-7\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}12x-8y=-16\\12x-9y=-21\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}1y=5\\12x-9y=-21\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y=5\\12x-9.5=-21\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y=5\\x=2\end{matrix}\right.\)
Vậy hpt có n0 \(\left(x;y\right)=\left(2;5\right)\)
Theo đề bài ta có:
\(P=\left(x-3\right)^{19}+\left(y-4\right)^5\)
\(P=\left(2-3\right)^{19}+\left(5-4\right)^5\)
\(P=\left(-1\right)^{19}+1^5\)
\(P=\left(-1\right)+1=0\)
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