Chỗ căn là : \(\sqrt{x}\) hay là \(\sqrt{x-2}\) vậy bạn.
TH: \(\sqrt{x}\)
\(2\sqrt{x}-2+2\sqrt{x}-2=8\) \(ĐK:x\ge0\)
\(\Leftrightarrow4\sqrt{x}=12\)
\(\Leftrightarrow\sqrt{x}=3\)
\(\Leftrightarrow x=9\left(TM\right)\)
TH: \(\sqrt{x-2}\)
\(2\sqrt{x-2}+2\sqrt{x-2}=8\) \(ĐK:x\ge2\)
\(\Leftrightarrow4\sqrt{x-2}=8\)
\(\Leftrightarrow\sqrt{x-2}=2\)
\(\Leftrightarrow x-2=4\)
\(\Leftrightarrow x=6\left(TM\right)\)
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