Câu 3
\(\Delta=1-4\left(-1\right).3=1+12=13>0\)
vậy pt luôn có 2 nghiệm pb
Theo Vi et \(\left\{{}\begin{matrix}x_1+x_2=\dfrac{1}{3}\\x_1x_2=-\dfrac{1}{3}\end{matrix}\right.\)
Ta có \(A=\left(x_1+x_2\right)^2-2x_1x_2=\dfrac{1}{9}-2\left(-\dfrac{1}{3}\right)=\dfrac{1}{9}+\dfrac{2}{3}=\dfrac{7}{9}\)