3\(\sqrt{x-2}\)+ 2\(\dfrac{\sqrt{x-2}}{2}\)-\(\dfrac{1}{2}\)2\(\sqrt{x-2}\)=12
3\(\sqrt{x-2}\)+\(\sqrt{x-2}\)-\(\sqrt{x-2}\)=12
(3+1-1)\(\sqrt{x-2}\)=12
3\(\sqrt{x-2}\)=12
\(\sqrt{x-2}\)=4
x - 2 = 4 hoặc x - 2 = -4
vậy x = 6 , x= - 2
3√x−2x−2+ 212122√x−2x−2=12
3√x−2x−2+√x−2x−2-√x−2x−2=12
(3+1-1)√x−2x−2=12
3√x−2x−2=12
√x−2x−2=4
x - 2 = 4 hoặc x - 2 = -4
vậy x = 6 , x= - 2