PTHH:2H2+O2→2H2O
Ta có : nH2=5(mol)
⇒nH2O=nH2=5(mol)
=> mH2O=5*18=90g
Mà DH2O=1g/ml
=> VH2O lỏng=90.1=90ml
nH2=\(\frac{112}{22,4}\)=5(mol)
2H2+O2→2H2O
nH2O = nH2= 5 (mol)
VH2O=22,4.5=112 l
\(PTHH:2H_2+O_2\rightarrow2H_2O\)
Ta có : \(n_{H2}=5\left(mol\right)\)
\(\Rightarrow n_{H2O}=n_{H2}=5\left(mol\right)\)
\(\Rightarrow V_{H2O}=122l\)