Question

tìm x biết

\(\left(x-\dfrac{1}{2}\right)^2=\dfrac{1}{4}\)

Answer 1

\(\left(x-\dfrac{1}{2}\right)^2=\dfrac{1}{4}\)

\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=\dfrac{1}{2}\\x-\dfrac{1}{2}=-\dfrac{1}{2}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=1\\x=0\end{matrix}\right.\)

Answer 2

\(TH1\left(x-\dfrac{1}{2}\right)^2=\left(\dfrac{1}{2}\right)^2\\ x-\dfrac{1}{2}=\dfrac{1}{2}\\ x=\dfrac{1}{2}+\dfrac{1}{2}\\ x=1\\ TH2\left(x-\dfrac{1}{2}\right)^2=\left(-\dfrac{1}{2}\right)^2\\ x-\dfrac{1}{2}=-\dfrac{1}{2}\\ x=-\dfrac{1}{2}+\dfrac{1}{2}\\ x=0\)

Answer 3

=>x-1/2=1/2 hoặc x-1/2=-1/2

=>x=0 hoặc x=1

Answer 4

`=>` \(\left[{}\begin{matrix}x-\dfrac{1}{2}=\dfrac{1}{2}\\x-\dfrac{1}{2}=-\dfrac{1}{2}\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}x=1\\x=0\end{matrix}\right.\)