Question

Tìm x biết:

\(\dfrac{1}{4}\)+\(\dfrac{1}{3}\):3x=-5

Answer 1

\(\dfrac{1}{4}+\dfrac{1}{3}:3x=-5\)

\(\Leftrightarrow\dfrac{1}{4}+\dfrac{1}{9x}=-5\)

\(\Leftrightarrow\dfrac{1}{9x}=-5-\dfrac{1}{4}\)

\(\Leftrightarrow\dfrac{1}{9x}=-\dfrac{21}{4}\)

\(\Leftrightarrow\left(-21\right)\cdot9x=4\)

\(\Leftrightarrow x=\dfrac{-4}{189}\)

Answer 2

`1/4+1/3:3x=-5`

`1/4+1/9x=-5`

`1/9x=-5-1/4=-21/4`

`x=-189/4`

Vậy `x=-189/4`

Answer 3

Nhầm xin lỗi :(

`1/4+1/3:3x=-5`

`1/4+1/(9x)=-5`

`1/(9x)=-5-1/4=-21/4`

`x=-4/189`

Vậy `x=-4/189`

Answer 4

\(\dfrac{1}{4}\) + \(\dfrac{1}{3}\) : 3x = -5

\(\dfrac{1}{3}\)  : 3x = -5 - \(\dfrac{1}{4}\)​​

​\(\dfrac{1}{3}\) : 3x = \(\dfrac{-21}{4}\)​

      3x = ​\(\dfrac{1}{3}\) : ​​\(\dfrac{-21}{4}\)​

      3x = \(\dfrac{1}{3}\) . \(\dfrac{-4}{21}\)

      3x = \(\dfrac{-4}{63}\)

        x = \(\dfrac{-4}{63}\): 3

        x = \(\dfrac{-4}{63}\). \(\dfrac{1}{3}\)

        x = \(\dfrac{-4}{189}\)

Answer 5

\(\dfrac{1}{4}+\dfrac{1}{3}:3x=-5\) 

             \(\dfrac{1}{9}x=-5-\dfrac{1}{4}\) 

             \(\dfrac{1}{9x}=\dfrac{-21}{4}\) 

\(\Rightarrow9x=\dfrac{4.1}{-21}=\dfrac{-4}{21}\) 

\(\Rightarrow9x=\dfrac{-4}{21}\) 

\(\Rightarrow x=\dfrac{-4}{21}:9=\dfrac{-4}{189}\)