Question

Tìm x biết:

(2x-2)³ = (2x-2)¹²

^{mọi người ơi giúp em với}

 

 

Answer 1

\(\left(2x-2\right)^3=\left(2x-2\right)^{12}\)

\(\Rightarrow\left(2x-2\right)^{15}\)

\(\Rightarrow2x-2=0\Rightarrow2x=2\Rightarrow x=1\)

Answer 2

\(\left(2x-2\right)^3=\left(2x-2\right)^{12}\)

\(\Rightarrow\left(2x-2\right)^9=1\)

\(\Rightarrow2x-2=1\)

\(\Rightarrow2x=3\Rightarrow x=\dfrac{3}{2}\)

Answer 3

\(\left(2x-2\right)^3=\left(2x-2\right)^{12}\\ \Rightarrow\left[{}\begin{matrix}2x-2=0\\2x-2=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{3}{2}\end{matrix}\right.\)

Answer 4

\(\left(2x-2\right)^3=\left(2x-2\right)^{12}\)

\(\Rightarrow\left[{}\begin{matrix}2x-2=0\\2x-2=1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{3}{2}\end{matrix}\right.\)

Answer 5

Ta có: \(\left(2x-2\right)^{12}=\left(2x-2\right)^3\)

\(\Leftrightarrow\left(2x-2\right)^3\cdot\left[\left(2x-2\right)^9-1\right]=0\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-2=0\\2x-2=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{3}{2}\end{matrix}\right.\)