\(\dfrac{2}{2+\sqrt{5}}+2\sqrt{5}=\dfrac{2\left(2-\sqrt{5}\right)}{4-5}+2\sqrt{5}\)
\(=\dfrac{4-2\sqrt{5}}{-1}+2\sqrt{5}\)
\(=-4+2\sqrt{5}+2\sqrt{5}\)
\(=-4+4\sqrt{5}\)
Ta có: \(\dfrac{2}{\sqrt{5}+2}+2\sqrt{5}\)
\(=2\sqrt{5}-4+2\sqrt{5}\)
\(=4\sqrt{5}-4\)