Question

\(\left(a^2+4\right)^2-16a^2\)

Answer 1

\(\left(a^2+4\right)^2-16a^2=\left(a^2+4+4a\right)\left(a^2+4-4a\right)=\left(a+2\right)^2\left(a-2\right)^2\)

Answer 2

Đề ? Phân tích đa thức thành nhân tử ?

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Ta có \(\left(a^2+4\right)^2-16a^2\) = \(\left(a+4\right)^2-\left(4a\right)^2=\left(a+4-4a\right)\left(a+4+4a\right)\)=\(\left(a-2\right)^2\left(a+2\right)^2\)

Answer 3

\(\left(a^2+4\right)^2-16a^2\)

\(=\left(a^2+4\right)^2-\left(4a\right)^2\)

\(=\left(a^2+4-4a\right)\left(a^2+4+4a\right)\)

\(=\left(a-2\right)^2\left(a+2\right)^2\)