d nhận \(\left(m-2;-4\right)\) là 1 vtpt
\(\Delta\) nhận \(\left(7;-1\right)\) là 1 vtpt
Ta có:
\(cos45^0=\frac{\left|7\left(m-2\right)+4\right|}{\sqrt{\left(m-2\right)^2+4^2}.\sqrt{7^2+1^2}}\)
\(\Leftrightarrow\frac{\left|7m-10\right|}{\sqrt{m^2-4m+20}.\sqrt{50}}=\frac{1}{\sqrt{2}}\)
\(\Leftrightarrow\left|7m-10\right|=\sqrt{25m^2-100m+500}\)
\(\Leftrightarrow\left(7m-10\right)^2=25m^2-100m+500\)
\(\Leftrightarrow3m^2-5m-50=0\)
\(\Rightarrow m_1+m_2=\frac{5}{3}\)