Question

Giải giúp mk bài này với mn ơi :(

Answer 1

a) \(\dfrac{3}{7}+\left(-\dfrac{5}{2}\right)+\left(-\dfrac{3}{7}\right)=\dfrac{3}{7}-\dfrac{5}{2}-\dfrac{3}{7}=-\dfrac{5}{2}\)

b) \(B=\dfrac{4^2.2^3}{2^6}=\dfrac{\left(2^2\right)^2.2^3}{2^6}=\dfrac{2^4.2^3}{2^6}=\dfrac{2^7}{2^6}=2\)

Answer 2

a, \(A=\dfrac{3}{7}-\dfrac{5}{2}-\dfrac{3}{7}=-\dfrac{5}{2}\)

b, \(B=\dfrac{4^2.2^3}{2^6}=\dfrac{2^4.2^3}{2^6}=\dfrac{2^7}{2^6}=2\)

Answer 3

\(A=\dfrac{3}{7}+(-\dfrac{5}{2})+(-\dfrac{3}{7})\)

\(=(\dfrac{3}{7}-\dfrac{3}{7})-\dfrac{5}{2} \)

\(=-\dfrac{5}{2}\)

\(B=\dfrac{4^2.2^3}{2^6}\)

\(B=\dfrac{4^2}{2^3}\)

\(B=\dfrac{16}{8}\)

\(B=2\)

Answer 4

\(A=\dfrac{3}{7}+\left(-\dfrac{5}{2}\right)+\left(-\dfrac{3}{7}\right)=\dfrac{3}{7}-\dfrac{3}{7}-\dfrac{5}{2}=-\dfrac{5}{7}\)

\(B=\dfrac{4^2.2^3}{2^6}=\dfrac{2^7}{2^6}\)

 

Answer 5

a: \(A=\dfrac{3}{7}+\left(-\dfrac{5}{2}\right)+\left(-\dfrac{3}{7}\right)=-\dfrac{5}{2}\)

b: \(B=\dfrac{4^2\cdot2^3}{2^6}=\dfrac{2^7}{2^6}=2\)