Question

\(\dfrac{x}{3}\) -2 < \(\dfrac{x-2}{4}\)

giải bất phương trình

Answer 1

   `x / 3 - 2 < [ x - 2 ] / 4`

`<=> [ 4x - 24 ] / 12 < [ 3 ( x - 2 ) ] / 12`

`<=> 4x - 24 < 3x - 6`

`<=> 4x - 3x < - 6 + 24`

`<=> x < 18`

Vậy `S = { x | x < 18 }`

Answer 2

\(\Leftrightarrow\dfrac{4x-24-3\left(x-2\right)}{12}< 0\)

\(\Leftrightarrow4x-24-3x+6< 0\)

\(\Leftrightarrow x-18< 0\)

\(\Leftrightarrow x< 18\)