\(x=\dfrac{0,13.42}{9}=\dfrac{91}{150}\)
`(0,13)/x = 9/42`
`(0,13)/x=3/14`
`0,13 . 14 = 3.x`
`0,52=3x`
`x=13/75`
\(\dfrac{0,13}{x}=\dfrac{9}{42}\)\(=\dfrac{0,13x42}{9}\)\(=\dfrac{91}{150}\)
\(x\) là dấu x!
\(x=\dfrac{0,13.42}{9}=\dfrac{91}{150}\)
`(0,13)/x = 9/42`
`(0,13)/x=3/14`
`0,13 . 14 = 3.x`
`0,52=3x`
`x=13/75`
\(\dfrac{0,13}{x}=\dfrac{9}{42}\)\(=\dfrac{0,13x42}{9}\)\(=\dfrac{91}{150}\)
\(x\) là dấu x!
a \(\dfrac{-4}{7}\) - \(\dfrac{5}{13}\) x \(\dfrac{-39}{25}\) + \(\dfrac{-1}{42}\) : \(\dfrac{-5}{6}\)
b \(\dfrac{2}{9}\) x [\(\dfrac{4}{45}\): ( \(\dfrac{1}{5}\) - \(\dfrac{2}{15}\)) + 1\(\dfrac{2}{3}\)] - \(\dfrac{-5}{27}\)
1) 11x=8y và y-x= -42
2) \(\dfrac{x}{y}\) =\(\dfrac{9}{7}\)=\(\dfrac{y}{z}\) =\(\dfrac{7}{3}\) và x-y+z=- 15
3) \(\dfrac{x}{-7}\) = \(\dfrac{y}{4}\) và 2x-3y= -78
A=\(\dfrac{38}{50}\)+\(\dfrac{9}{20}\)-\(\dfrac{11}{30}\)+\(\dfrac{13}{42}\)-\(\dfrac{15}{56}\)+\(\dfrac{17}{72}\)-...+\(\dfrac{197}{9702}\)-\(\dfrac{199}{9900}\)
tính hợp lí:
\(\dfrac{8}{9}-\dfrac{1}{72}-\dfrac{1}{56}-\dfrac{1}{42}-\dfrac{1}{30}-\dfrac{1}{20}-\dfrac{1}{12}-\dfrac{1}{6}-\dfrac{1}{2}\)
Tính:
\(A=\dfrac{8}{9}-\dfrac{1}{72}-\dfrac{1}{56}-\dfrac{1}{42}-...-\dfrac{1}{6}-\dfrac{1}{2}\)
Giải chi tiết giúp mik nha.
\(\dfrac{x}{2}\)=\(\dfrac{y}{3}\);\(\dfrac{y}{3}\)=\(\dfrac{z}{4}\)và x+y+z=-42
a, \(\dfrac{x}{6}=\dfrac{y}{-3}\) và x - y = 27
b,
\(\dfrac{x}{8}=\dfrac{y}{1,5}\) và x - 4y = -0,2
c, \(\dfrac{x}{y}=\dfrac{11}{13}\) và 2x + 3y = 122
d, 3x - 2y = 42 và \(\dfrac{x}{y}=\dfrac{5}{-3}\)
e, 3x = 5y và y - x = -10,2
Tìm x trong các tỉ lệ thức sau:
a)\(\dfrac{-2,6}{x}=\dfrac{-12}{42}\) b)2,5:x=1,5:12
c)\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\) d)\(\dfrac{x}{6}=\dfrac{24}{25x}\) e)\(\dfrac{x-2}{9}=\dfrac{4}{x-2}\)
cho \(\dfrac{x}{5}=\dfrac{y}{2}\); x+y= -42 thì x bằng