Đâu là một hỗn số:
A.\(1\dfrac{5}{2}\) B.\(2\dfrac{1}{3}\) C.\(2\dfrac{4}{3}\) D.\(3\dfrac{4}{3}\)
a, \(\dfrac{1}{3}-\dfrac{1}{4}:\dfrac{2}{5}\)
b, \(\dfrac{6}{7}-\left(\dfrac{5}{6}+\dfrac{1}{3}\right)-\left(\dfrac{2}{3}+\dfrac{1}{7}\right)\)
c, \(\dfrac{-5}{9}.\dfrac{2}{5}+4\dfrac{5}{9}+\dfrac{5}{9}.\dfrac{-3}{5}\)
d, \(3\dfrac{1}{2}-\left(5\dfrac{4}{7}-1\dfrac{1}{2}\right):0,75\)
Thực hiện phép tính: a) \(11\dfrac{3}{4}-\left(6\dfrac{5}{6}-4\dfrac{1}{2}\right)+1\dfrac{2}{3}\)
b) \(2\dfrac{17}{20}-1\dfrac{11}{15}+6\dfrac{9}{20}:3\) c) \(4\dfrac{3}{7}:\left(\dfrac{7}{5}.4\dfrac{3}{7}\right)\)
d) \(\left(3\dfrac{2}{9}.\dfrac{15}{23}.1\dfrac{7}{29}\right):\dfrac{5}{23}\)
3. Tính :
a/ \(\dfrac{-1}{2}\) + \(\dfrac{5}{6}\) + \(\dfrac{1}{3}\) b/ \(\dfrac{-3}{8}\) + \(\dfrac{7}{4}\) - \(\dfrac{1}{12}\) c/ \(\dfrac{3}{5}\) : (\(\dfrac{1}{4}\) . \(\dfrac{7}{5}\)) d/ \(\dfrac{10}{11}\) + \(\dfrac{4}{11}\) : 4 - \(\dfrac{1}{8}\)
Điền dấu thích hợp (>,<,=) vào chỗ trống.
a,\(\dfrac{-6}{11}+\dfrac{5}{-11}....--1\) b.\(\dfrac{-5}{16}+\dfrac{-3}{16}...\dfrac{-1}{3}\)
c,\(\dfrac{2}{5}...\dfrac{3}{4}+\dfrac{-1}{6}\) d,\(\dfrac{5}{6}+\dfrac{-2}{3}...\dfrac{1}{12}+\dfrac{-4}{5}\)
Giúp mk nha :>>. Mk cảm ơn.
Dãy phân số sắp xếp theo thứ tự tăng dần là:
\(A.\dfrac{1}{2};\dfrac{1}{4};\dfrac{1}{6};\dfrac{1}{5}\) \(B.\dfrac{1}{6};\dfrac{1}{5};\dfrac{1}{4};\dfrac{1}{2}\)
\(C.\dfrac{1}{2};\dfrac{1}{6};\dfrac{1}{5};\dfrac{1}{4}\) \(D.\dfrac{1}{2};\dfrac{1}{4};\dfrac{1}{5};\dfrac{1}{6}\)
Câu 3: Phân số nào sau đây không tối giản?
A. | B. \(\dfrac{1}{4}\). | C. | D. |
Tính:
a) \(\dfrac{13}{14}\)-\(\dfrac{-7}{8}\)+\(\dfrac{-3}{2}\)
b) \(\dfrac{5}{17}\)+\(\dfrac{-15}{34}\).\(\dfrac{2}{5}\)
c) \(\dfrac{1}{5}\):\(\dfrac{1}{10}\)-\(\dfrac{1}{3}\).(\(\dfrac{6}{5}\)-\(\dfrac{2}{4}\))
d) \(\dfrac{-3}{4}\):(\(\dfrac{12}{-5}\)-\(\dfrac{-7}{10}\))
*Lưu ý: Không viết luôn kết quả, giải chi tiết.
a) A = \(\dfrac{19}{9}-\dfrac{-4}{11}-\dfrac{2}{-3}\)
b) B = \(\dfrac{-5}{6}+\dfrac{-7}{12}-\dfrac{1}{-5}\)
c) C = \(\dfrac{-3}{4}+\dfrac{11}{3}-\dfrac{-5}{18}\)
d) D = \(\dfrac{-19}{3}-\dfrac{4}{5}-\dfrac{-2}{3}\)