a: \(=0\)
b: \(=49y^2-28y+4-49y^2+1=-28y+5\)
c: \(=4\left(4x^2+4x+1\right)-\left(16x^2+8x+1\right)\)
\(=16x^2+16x+4-16x^2-8x-1=8x+3\)
a: \(=0\)
b: \(=49y^2-28y+4-49y^2+1=-28y+5\)
c: \(=4\left(4x^2+4x+1\right)-\left(16x^2+8x+1\right)\)
\(=16x^2+16x+4-16x^2-8x-1=8x+3\)
Viết các biểu thức sau dưới dạng bình phương của một tổng hoặc hiệu
f) \(2xy^2+x^2y^2+1\)
g) \(\left(3x-2y\right)^2+2\left(3x-2y\right)+1\)
h) \(16-8\left(x-3y\right)+\left(x-3y\right)^2\)
i) \(2\left(x-y\right)\left(x+y\right)+\left(x+y\right)^2+\left(x-y\right)^2\)
j) \(\left(x+y-z\right)^2+\left(y-z\right)^2+2\left(x+y-z\right)\left(z-y\right)\)
Thu gọn: \(\left(x-y+z\right)^2-\left(2x-y+1\right)^2-\left(y-z+2\right)^2+\left(2x-1\right)^2-3\left(2y-3z\right)^2\)
Chứng minh rằng nếu:\(\left(x-y\right)^2+\left(y-z\right)^2+\left(z-x\right)^2=\left(y+z-2x\right)^2+\left(z+x-2y\right)^2+\left(x+y-2z\right)^2\)thì x=y=z
1. tính
a) \(\left(\dfrac{2}{3}x-\dfrac{3}{2}y\right)^2\)
b) \(\left(\dfrac{1}{2}x^2+\dfrac{1}{3}\right)^2\)
c) \(\left(x+\dfrac{1}{5}y^2\right)\left(x-\dfrac{1}{5}y^2\right)\)
d) \(\left(\dfrac{1}{2}x-2y\right)^3\)
e) \(\left(-\dfrac{1}{2}xy^2+x\right)^3\)
f) \(27x^3-8y^3\)
g) 4(2x - 3y) - 4 - (2x-3y)2
2. rút gọn
a) \(2m\left(5m+2\right)+\left(2m-3\right)\left(3m-1\right)\)
b) \(\left(2x+4\right)\left(8x-3\right)-\left(4x+1\right)^2\)
c) \(\left(7y-2\right)^2-\left(7y+1\right)\left(7y-1\right)\)
d) \(\left(a+2\right)^3-a\left(a-3\right)^2\)
3. c/m các biểu thức sau ko phụ thuộc vào biến x,y
a) \(\left(2x-5\right)\left(2x+5\right)-\left(2x-3\right)^2-12x\)
b) \(\left(2y-1\right)^3-2y\left(2y-3\right)^2-6y\left(2y-2\right)\)
c) \(\left(x+3\right)\left(x^2-3x+9\right)-\left(20+x^3\right)\)
d) \(3y\left(-3y-2\right)^2-\left(3y-1\right)\left(9y^2+3y+1\right)-\left(-6y-1\right)^2\)
4. Tìm x
a) \(\left(2x+5\right)\left(2x-7\right)-\left(-4x-3\right)^2=16\)
b) \(\left(8x^2+3\right)\left(8x^2-3\right)-\left(8x^2-1\right)^2=22\)
c) \(49x^2+14x+1=0\)
d) \(\left(x-1\right)^3-x\left(x-2\right)^2-\left(x-2\right)=0\)
5. c/m biểu thức luôn dương:
a) \(A=16x^2+8x+3\)
b) \(B=y^2-5y+8\)
c) C= \(2x^2-2x+2\)
d) \(D=9x^2-6x+25y^2+10y+4\)
6. Tìm GTLN và GTNN của các biểu thức sau
a) \(M=x^2+6x-1\)
b) \(N=10y-5y^2-3\)
7. thu gọn
a) \(\left(2+1\right)\left(2^2+1\right)\left(2^3+1\right)...\left(2^{32}+1\right)-2^{64}\)
b) \(\left(5+3\right)\left(5^2+3^2\right)\left(5^4+3^4\right)...\left(5^{\text{64}}+3^{64}\right)+\dfrac{5^{128}-3^{128}}{2}\)
Rút gọn biểu thức :
a) \(\left(x+y\right)^2+\left(x-y\right)^2\)
b) \(2\left(x-y\right)\left(x+y\right)+\left(x+y\right)^2+\left(x-y\right)^2\)
c) \(\left(x-y+z\right)^2+\left(z-y\right)^2+2\left(x-y+z\right)\left(y-z\right)\)
Chứng minh các đẳng thức sau :
\(\left(\dfrac{2x+2y-z}{3}\right)^2+\left(\dfrac{2y+2z-x}{3}\right)^2+\left(\dfrac{2z+2x-y}{3}\right)^2=x^2+y^2+z^2\)
Tính theo kiểu hằng đẳng thức mở rộng
a) \(\left(x+2y\right)^3\)
b)\(\left(2x-y\right)^3\)
c)\(\left(x^2+x+1\right).\left(x-1\right)\)
d) \(\left(4x^2-2x+1\right).\left(2x+1\right)\)
rút gọn biểu thức
a) \(\left(x+y\right)^2+\left(x-y\right)^2\)
b) 2 ( x - y ) ( x + y ) + \(\left(x+y\right)^2+\left(x-y\right)^2\)
c)\(\left(x-y+z\right)^2-\left(z-y\right)^2+2\left(x-y+z\right)\left(y-z\right)\)
Rút gọn biểu thức:
a) \(A=\left(x-y\right)^3+\left(y+x\right)^3+\left(y-x\right)^3-3xy\left(x+y\right)\)
b) \(B=3x^2\left(x+1\right)\left(x-1\right)-\left(x^2-1\right)\left(x^4+x^2+1\right)+\left(x^2-1\right)^3\)
c) \(C=\left(x+y\right)\left(x^2-xy+y^2\right)+\left(x-y\right)\left(x^2+xy+y^2\right)-2x^3\)
d) \(D=\left(x+1\right)^3+\left(x-1\right)^3+x^3-3x\left(x+1\right)\left(x-1\right)\)
Chứng minh nếu \(x^2=b^2+c^2;y^2=c^2+a^2;z^2=a^2+b^2\)thì \(\left(x+y+z\right)\left(-x+y+z\right)\left(x-y+z\right)\left(x+y-z\right)=4\left(a^2b^2+b^2c^2+c^2a^2\right)\)