ĐK: x > 0
\(\Rightarrow2\sqrt{3}x=2\sqrt{x}\)
\(\Rightarrow\sqrt{3}x-\sqrt{x}=0\)
\(\Rightarrow\sqrt{x}\left(\sqrt{3x}-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{3}\end{matrix}\right.\)
Vì x > 0 => x = 1/3
\(2\sqrt{3}=\dfrac{2\sqrt{x}}{x}\left(ĐK:x>0\right)\)
\(\Leftrightarrow\dfrac{2x\sqrt{3}}{x}=\dfrac{2\sqrt{x}}{x}\)
\(\Leftrightarrow2x\sqrt{3}=2\sqrt{x}\)
\(\Leftrightarrow2x\sqrt{3}-2\sqrt{x}=0\)
\(\Leftrightarrow x\sqrt{3}-\sqrt{x}=0\)
\(\Leftrightarrow\sqrt{x}\left(\sqrt{3x}-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x}=0\\\sqrt{3x}-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\left(loại\right)\\x=\dfrac{1}{3}\left(TM\right)\end{matrix}\right.\)
