Question

|-1/3+x|=0,4

Answer 1

x 
1
​
 =−0.0 
6
˙
 ,x 
2
​
 =0.7 
3
˙

Answer 2

\(\left|-\dfrac{1}{3}+x\right|=0,4\)

\(\left[{}\begin{matrix}-\dfrac{1}{3}+x=0,4\\-\dfrac{1}{3}+x=-0,4\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=0,4-\left(-\dfrac{1}{3}\right)\\x=-0,4-\left(-\dfrac{1}{3}\right)\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=\dfrac{11}{15}\\x=-\dfrac{1}{15}\end{matrix}\right.\)

Answer 3

\(\left(\dfrac{-1}{3}+x\right)=0,4\)

\(\Rightarrow\dfrac{-1}{3}+x=\dfrac{4}{10}\)

\(\Rightarrow x=\dfrac{4}{10}-\dfrac{-1}{3}\)

\(\Rightarrow x=\dfrac{11}{15}\)

Answer 4

`|-1/3+x|=0,4`

`|-1/3+x|=4/10`

`|-1/3+x|=2/5`

`+` TH1: `-1/3 +x=2/5`

`x=2/5 - (-1/3)`

`x=2/5 + 1/3`

`x=6/15 + 5/15`

`x=11/15`

`+` TH2: `-1/3 +x=-2/5`

`x=-2/5 - (-1/3)`

`x=-2/5 + 1/3

`x=-6/15 + 5/15`

`x=-1/15`

Vậy `x` \(\in\) `{11/15;-1/15}`

Answer 5

|-1/3+x|=0,4

=> `-1/3+x=0,4 ` hoặc ` -1/3+x=-0,4`

=> `x=11/15` hoặc `x-1/15`

Answer 6

\(\left|-\dfrac{1}{3}+x\right|=0,4\)
\(\Rightarrow\left[{}\begin{matrix}-\dfrac{1}{3}+x=0,4\\-\dfrac{1}{3}+x=-0,4\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}-\left(-\dfrac{1}{3}\right)\\x=-\dfrac{2}{5}-\left(-\dfrac{1}{3}\right)\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{6}{15}+\dfrac{5}{15}\\x=-\dfrac{6}{15}+\dfrac{5}{15}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{11}{15}\\x=-\dfrac{1}{15}\end{matrix}\right.\)

Answer 7

\(\left|-\dfrac{1}{3}+x\right|=0,4\)

\(\Leftrightarrow\left[{}\begin{matrix}-\dfrac{1}{3}+x=0,4\\-\dfrac{1}{3}+x=-0,4\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0,4+\dfrac{1}{3}\\x=-0,4+\dfrac{1}{3}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{11}{15}\\x=-\dfrac{1}{15}\end{matrix}\right.\)

Answer 8

`|-1/3+x|=0,4`

`=>|-1/3+x|=2/5`

\(\Rightarrow\left[{}\begin{matrix}-\dfrac{1}{3}+x=\dfrac{2}{5}\\-\dfrac{1}{3}+x=-\dfrac{2}{5}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}-\left(-\dfrac{1}{3}\right)\\x=-\dfrac{2}{5}-\left(-\dfrac{1}{3}\right)\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}+\dfrac{1}{3}\\x=-\dfrac{2}{5}+\dfrac{1}{3}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{11}{15}\\x=-\dfrac{1}{15}\end{matrix}\right.\)