\(a,5-\left(x-6\right)=4\left(3-2x\right)\\ =>5-x+6=12-8x\\ =>-x+8x=12-5-6\\ =>7x=1\\ =>x=\dfrac{1}{7}\\ b,2x\left(x+2\right)^2-8x^2=2\left(x-2\right)\left(x^2+2x+4\right)\\ =>2x\left(x^2+4x+4\right)-8x^2=2.\left(x^3-8\right)\\ =>2x^3+8x^2+8x-8x^2-2x^3+16=0\\ =>8x=-16\\ =>x=-2\)
\(c,7-\left(2x+4\right)=-\left(x+4\right)\\ =>7-2x-4=-x-4\\ =>-2x+x=-4+4-7\\ =>-x=-7\\ =>x=7\\ d,\left(x-2\right)^3+\left(3x-1\right)\left(3x+1\right)=\left(x+1\right)^3\\ =>x^3-6x^2+12x-8+9x^2-1=x^3+3x^2+3x+1\\ =>x^3-x^3+3x^2+12x-9-3x^2-3x-1=0\\ =>9x-10=0\\ =>x=\dfrac{10}{9}\)
e: =>2x^2-3x+2x-3=2x^2+10x-x-5
=>9x-5=-x-3
=>10x=2
=>x=1/5
f: \(\Leftrightarrow x^3-3x^2+3x-1-x^3-2x^2-x=10x-5x^2-11x-22\)
=>\(-5x^2+2x-1=-5x^2-11x-22\)
=>2x-1=-11x-22
=>13x=-21
=>x=-21/13
g: =>x-1-2x+1=9-x
=>-x=9-x
=>\(x\in\varnothing\)
h: =>x^2+x-12-6x+4=x^2-8x+16
=>-5x-8=-8x+16
=>3x=24
=>x=8
i: =>x^3+6x^2+9x-3x=x^3+6x^2+12x+8+1
=>6x^2+6x=6x^2+12x+9
=>12x+9=6x
=>6x=-9
=>x=-3/2
j: =>x^3+1-2x=x^3-x
=>x=-2x+1
=>3x=1
=>x=1/3
