\(a)\)\(x-\dfrac{4}{3}\) \(=\dfrac{5}{3}\)
\(x=\dfrac{5}{3}\) \(+\dfrac{4}{3}\)
\(x=\dfrac{9}{3}\)
\(x=3\)
\(x-\dfrac{4}{5}=\dfrac{5}{3}\)
\(x=\dfrac{5}{3}+\dfrac{4}{3}\)
\(x=\dfrac{9}{3}=3\)
x-\(\dfrac{4}{3}=\dfrac{5}{3}\)
x=\(\dfrac{5}{3}+\dfrac{4}{3}\)
x=3
Vậy x=3