ĐKXĐ: ...
\(\Leftrightarrow\left(x+\dfrac{x}{x-1}\right)^3-3x.\dfrac{x}{x-1}\left(x+\dfrac{x}{x-1}\right)+\dfrac{3x^2}{x-1}-2=0\)
\(\Leftrightarrow\left(\dfrac{x^2}{x-1}\right)^3-3\left(\dfrac{x^2}{x-1}\right)^2+\dfrac{3x^2}{x-1}-1-1=0\)
\(\Leftrightarrow\left(\dfrac{x^2}{x-1}-1\right)^3-1=0\)
\(\Leftrightarrow\dfrac{x^2}{x-1}-1=1\)
\(\Rightarrow x^2-2x+2=0\)
Phương trình đã cho vô nghiệm