\(\dfrac{2x}{x^2-4x+4}=\dfrac{2x}{\left(x-2\right)^2}=\dfrac{2x\left(x-3\right)}{\left(x-2\right)^2\cdot\left(x-3\right)}=\dfrac{6x\left(x-3\right)}{3\left(x-2\right)^2\left(x-3\right)}\)
\(\dfrac{4}{3x-6}=\dfrac{4}{3\left(x-2\right)}=\dfrac{4\left(x-2\right)\left(x-3\right)}{3\left(x-2\right)^2\left(x-3\right)}\)