\(x+\dfrac{3}{4}=\dfrac{13}{12}\)
\(\Rightarrow x=\dfrac{13}{12}-\dfrac{3}{4}\)
\(\Rightarrow x=\dfrac{13}{12}-\dfrac{9}{12}\)
\(\Rightarrow x=\dfrac{1}{3}\)
\(x+\dfrac{3}{4}=\dfrac{13}{12}\)
\(x=\dfrac{3}{4}-\dfrac{13}{12}\)
\(x=-\dfrac{1}{3}\)
\(x=\dfrac{13}{12}-\dfrac{3}{4}\)
\(x=\dfrac{1}{3}\)
Vậy \(x=\dfrac{1}{3}\)
\(x+\dfrac{3}{4}=\dfrac{13}{12}\)
\(\Leftrightarrow x=\dfrac{13}{12}-\dfrac{3}{4}=\dfrac{13}{12}-\dfrac{9}{12}=\dfrac{4}{12}=\dfrac{1}{3}\)