\(Sửa,đề:x^2-10x+25\\ =x^2-2x.5+5^2=\left(x-5\right)^2=\left(x-5\right)\left(x-5\right)\\---\\ b,x^3+125=x^3+5^3=\left(x+5\right)\left(x^2-5x+25\right)\\ ---\\ 8x^3-y^3=\left(2x\right)^3-y^3\\ =\left(2x-y\right)\left(4x^2+2xy+y^2\right)\)
a, Bạn xem lại đề vì không thể tách được.
b, \(x^3+125\\ =x^3+5^3=\left(x+5\right)\left(x^2-5x+25\right)\)
c, \(8x^3-y^3\\ =\left(2x\right)^3-y^3\\ =\left(2x-y\right)\left(4x^2+2xy+y^2\right)\)
a/
\(x^2-10x+25=x^2+2.x.5+5^2=\left(x-5\right)^2=\left(x-5\right)\left(x-5\right)\)
b/
\(x^3+125=x^3+5^3=\left(x+5\right)\left(x^2-5x+25\right)\)
c/
\(8x^3-y^3=\left(2x\right)^3-y^3=\left(2x-y\right)\left(4x^2+2xy+y^2\right)\)
