\(2+\dfrac{3}{5}=\dfrac{10}{5}+\dfrac{3}{5}=\dfrac{13}{5}\\ 2-\dfrac{3}{5}=\dfrac{10}{5}-\dfrac{3}{5}=\dfrac{7}{5}\)
\(2+\dfrac{3}{5}=\dfrac{2}{1}+\dfrac{3}{5}=\dfrac{10+3}{5}=\dfrac{13}{5}\)\
\(2-\dfrac{3}{5}=\dfrac{2}{1}-\dfrac{3}{5}=\dfrac{10-3}{5}=\dfrac{7}{5}\)
\(2+\dfrac{3}{5}=\dfrac{2}{1}+\dfrac{3}{5}=\dfrac{10}{5}+\dfrac{3}{5}=\dfrac{13}{5}\)
\(2-\dfrac{3}{5}=\dfrac{2}{1}-\dfrac{3}{5}=\dfrac{10}{5}-\dfrac{3}{5}=\dfrac{7}{5}\)