\(A=-\frac{1}{20}+-\frac{1}{30}+...+-\frac{1}{90}\)
\(=-\frac{1}{4.5}+-\frac{1}{5.6}+...+-\frac{1}{9.10}\)
\(=\left(-\frac{1}{4}\right)-\left(-\frac{1}{5}\right)+\left(-\frac{1}{5}\right)-\left(-\frac{1}{6}\right)+...+\left(-\frac{1}{9}\right)-\left(-\frac{1}{10}\right)\)
\(=\left(-\frac{1}{4}\right)-\left(-\frac{1}{10}\right)=-\frac{3}{20}\)
Vậy \(A=-\frac{3}{20}\)