`lim_{x->-oo}[3x^2-5x+2]/[x^4+2x^2-1]` `ĐK: x ne +-\sqrt{-1+\sqrt{2}}`
`=lim_{x->-oo}[3/[x^2]-5/[x^3]+2/[x^4]]/[1+2/[x^2]-1/[x^4]]`
`=0`
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27 tháng 1 2023 lúc 8:56
Tìm các giới hạn sau:limlimits_{xrightarrow-infty} dfrac{sqrt{x^6+2}}{3text{x}^3-1}limlimits_{xrightarrow+infty} dfrac{sqrt{x^6+2}}{3text{x}^3-1}limlimits_{xrightarrow-infty} left(sqrt{2text{x}^2+1}+xright)limlimits_{xrightarrow1} dfrac{2text{x}^3-5text{x}-4}{left(x+1right)^2}
Đọc tiếp
Tìm các giới hạn sau:
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\(\lim\limits_{x\rightarrow1}\) \(\dfrac{2\text{x}^3-5\text{x}-4}{\left(x+1\right)^2}\)
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