Question

Tính giá trị lượng giác (nếu có) của góc sau:

\(\dfrac{\pi}{3}+k2\pi\left(k\in Z\right)\)

Answer 1

\(\dfrac{\Omega}{3}+k2\Omega=\dfrac{\Omega}{3}\)

=>\(sin\left(\dfrac{\Omega}{3}+k2\Omega\right)=sin\left(\dfrac{\Omega}{3}\right)=\dfrac{\sqrt{3}}{2}\)

\(cos\left(\dfrac{\Omega}{3}+k2\Omega\right)=cos\left(\dfrac{\Omega}{3}\right)=\dfrac{1}{2}\)

\(tan\left(\dfrac{\Omega}{3}+k2\Omega\right)=tan\left(\dfrac{\Omega}{3}\right)=\sqrt{3}\)

\(cot\left(\dfrac{\Omega}{3}+k2\Omega\right)=cot\left(\dfrac{\Omega}{3}\right)=\dfrac{\sqrt{3}}{3}\)