Question

Tính giá trị biểu thức:
a) (3^3)^2               b) (2^5)^3:4^5       c)7^5:7^3-2021^0     d) 6^2.6^3:36+5^3:5^2

Answer 1

a: \(=3^6=729\)

b: \(=2^{15}:2^{10}=2^5=32\)

c: \(=7^2-1=49-1=48\)

d: \(=6^3+5=221\)

Answer 2

\(a,=3^6=729\\ b,=2^{15}:4^5=32768:1024\\ =32\\ c,=7^2-1\\ =49-1\\ =48\\ d,=6^2.6^3:6^2+5^1\\ =6^3+5\\ =216+5=221\)

Answer 3

a.(3^3)^2

= 27^2

= 729

b. (2^5)^3:4^5

= 32^3 : 1024

= 32768 : 1024

= 32

c.7^5:7^3-2021^0 

= 16807 : 343 - 0

= 49-0

= 49

d.6^2.6^3:36+5^3:5^2

= 36 . 216 : 36 + 125 : 25

= 126 + 5

= 131