Question

\(Tìm.x:\)

\(3\left(x-\dfrac{1}{2}\right)-5\left(x+\dfrac{3}{5}\right)=-x+\dfrac{1}{5}\)

\(vẫn.là.giải.chi.tiết\)

Answer 1

`3(x-1/2)-5(x+3/5)=-x+1/5`

`3x-3/2-5x-3=-x+1/5`

`3x-5x+x=1/5+3/2+3`

`-x=47/10`

`x=47/10:(-1)=[-47]/10`

Answer 2

\(3\left(x-\dfrac{1}{2}\right)-5\left(x+\dfrac{3}{5}\right)=-x+\dfrac{1}{5}\\ \Leftrightarrow3x-\dfrac{3}{2}-5x-3=-x+\dfrac{1}{5}\\ \Leftrightarrow3x-5x+x=\dfrac{1}{5}+3+\dfrac{3}{2}\\ \Leftrightarrow-x=\dfrac{47}{10}\\ \Leftrightarrow x=\dfrac{-47}{10}\)

Vậy \(x=\dfrac{-47}{10}\)

Answer 3

\(3\left(x-\dfrac{1}{2}\right)-5\left(x+\dfrac{3}{5}\right)=-x+\dfrac{1}{5}\)

\(\Leftrightarrow3x-\dfrac{3}{2}-5x-3+x-\dfrac{1}{5}=0\)

\(\Leftrightarrow-x-\dfrac{47}{10}=0\)

\(\Leftrightarrow-x=\dfrac{47}{10}\)

\(\Leftrightarrow x=\dfrac{-47}{10}\)