Question

tìm x

x^3-25x=0

Answer 1

Answer 2

x³-25x=0

 x(x²-25)=0

x(x²-5²)=0

x(x-5)(x+5)=0

=> x=0 ; x-5= 0 hoặc x+5= 0

=> x=0; x=5 hoặc x= -5

=> x ={ 0;5;-5}

 

 

Answer 3

x^3 - 25x = 0
<=> x( x^2 - 25) = 0
<=> x( x - 5)(x + 5) = 0
<=> x = 0
x -5 = 0
x + 5 = 0
<=> x = 0
x = 5
x = -5

Answer 4

x^3 - 25x = 0 <=> x( x^2 - 25) = 0 <=> x( x - 5)(x + 5) = 0 <=> x = 0 x -5 = 0 x + 5 = 0 <=> x = 0 x = 5 x = -5

Answer 5

x³-25x=0
x(x²-25)=0
x(x-5)(x+5)=0
TH1: x=0
TH2: x-5=0       TH3: x+5=0
            x=5                    x=-5
Vậy x\(\in\left\{0;5;-5\right\}\)

Answer 6

5

Answer 7

x³ - 25x = 0

x(x² - 25) = 0

x(x - 5)(x + 5) = 0

=> x = 0

hoặc x - 5 = 0 <=> x = 5

hoặc x + 5 = 0 <=> x = -5

Vậy x E {-5; 0; 5}