\(\text{(x + 2)^3 - 41 = 23}\\ \left(x+2\right)^3=23+41\\ \left(x+2\right)^3=64\\ x+2=4\\ x=4-2\\ x=2\)
Lời giải:
$(x+2)^3-41=23$
$\Leftrightarrow (x+2)^3=23+41=64=4^3$
$\Leftrightarrow x+2=4$
$\Leftrightarrow x=2$
\(\Leftrightarrow\left(x+2\right)^3=64\Leftrightarrow x+2=4\Leftrightarrow x=2\)
\(\Leftrightarrow\left(x+2\right)^3=23+41=64=4^3\\ \Leftrightarrow x+2=4\\ \Leftrightarrow x=2\)
<=> (x+2)3 =23+41
<=> (x+2)3 =64
<=> (x+2)3 = 43
<=>x+2 =4
<=> x =2