Question

Tìm x:

3x^3-12x^2+12x=0

Answer 1

`<=> 3x(x^2 - 4x + 4) = 0`

`=> 3x(x-2)^2 = 0`

`=>` \(\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

Answer 2

\(\Leftrightarrow3x\left(x^2-4x+4\right)=0\)

\(\Leftrightarrow3x\left(x-2\right)^2=0\)

=>x=0 hoặc x=2