Question

Tìm x: (Phân tích đa thức thành nhân tử)

( x + 1 )² = x + 1

Answer 1

\(\Rightarrow\left(x+1\right)^2-\left(x+1\right)=0\\ \Rightarrow\left(x+1\right)\left(x+1-1\right)=0\\ \Rightarrow x\left(x+1\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\)

Answer 2

(x + 1)² = x + 1

⇒ (x + 1)² - (x + 1)=  0

⇒ (x + 1) . (x + 1 - 1) =0

⇒  (x + 1) . x = 0

\(\Rightarrow\left[{}\begin{matrix}x+1=0\\x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-1\\x=0\end{matrix}\right.\)

Answer 3

\(\left(x+1\right)^2=x+1\Rightarrow\left(x+1\right)^2-\left(x+1\right)=0\)

\(\Rightarrow\left(x+1\right)\left(x+1-1\right)=0\) \(\Rightarrow x\left(x+1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\)

Answer 4

(x + 1)² = x + 1

<=> x² + 2x + 1 = x + 1

<=> x² + x = 0

<=> x(x + 1) = 0

<=> \(\left[{}\begin{matrix}x=0\\x+1=0\end{matrix}\right.\)

<=> \(\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\)

Answer 5

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