Question

tìm x biết 2021x(x-2020)-x+2020=0 mn giúp em với

Answer 1

\(2021x\left(x-2020\right)-x+2020=0\)

\(\Rightarrow2021x\left(x-2020\right)-\left(x-2020\right)=0\)

\(\Rightarrow\left(x-2020\right)\left(2021x-1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-2020=0\\2021x-1=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=2020\\x=\dfrac{1}{2021}\end{matrix}\right.\)

Answer 2

Ta có: \(2021x\left(x-2020\right)-x+2020=0\)

\(\Leftrightarrow\left(x-2020\right)\left(2021x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2020\\x=\dfrac{1}{2021}\end{matrix}\right.\)