Question

Tìm số tự nhiên biết:
X<7+\(\dfrac{1}{7}\)

Answer 1

\(7+\dfrac{1}{7}=\dfrac{7.7+1}{7}=\dfrac{50}{7}\simeq7,14\)

\(\Rightarrow X=7;6;5;4;3;2;1;0\)

Answer 2

\(x< 7+\dfrac{1}{7}\\ =>x< \dfrac{49}{7}+\dfrac{1}{7}\\ =>x< \dfrac{50}{7}\)

Answer 3

\(x< 7+\dfrac{1}{7}\\ \Rightarrow x< \dfrac{50}{7}\\ \Rightarrow x=0,1,2,3,4,5,6,7\)

Answer 4

x = 0,1,2,3,4,5,6,7

Answer 5

x = 0, 1, 2, 3, 4, 5, 6, 7