(\(x\) - 3).(3 + \(x\))
= 3\(x\) + \(x^2\) - 9 - 3\(x\)
= \(x^2\) - 9
\(\left(x-3\right)\left(3+x\right)\\ =\left(x-3\right).3+\left(x-3\right).x\\ =3x-9+2x-3x\\ =3x-9-x\\ =3x-x+9\\ =2x+9.\)
\(\left(x-3\right)\left(3+x\right)=-\left(3-x\right)\left(3+x\right)=-\left(9-x^2\right)=x^2-9\)
(x - 3)(3 + x)
= 3x + x² - 9 - 3x
= x² - 9
(x-3)(3+x)
=(x-3)(x+3)
=\(x^2\)-\(3^2\)
=\(x^2-9\)