\(=\dfrac{\sqrt{24-6\sqrt{7}}-\sqrt{24+6\sqrt{7}}}{\sqrt{2}}=\dfrac{\sqrt{21}-\sqrt{3}-\sqrt{21}-\sqrt{3}}{\sqrt{2}}=-\sqrt{6}\)
\(=\dfrac{\sqrt{24-6\sqrt{7}}-\sqrt{24+6\sqrt{7}}}{\sqrt{2}}=\dfrac{\sqrt{21}-\sqrt{3}-\sqrt{21}-\sqrt{3}}{\sqrt{2}}=-\sqrt{6}\)
tính \(\sqrt{7-2\sqrt{12}}\) kết quả là
a, \(7-2\sqrt[]{12}\)
b, \(2\sqrt{12}-7\)
c, 2-\(\sqrt{3}\)
d, \(\sqrt{3}-2\)
A = \(\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)
Tính A
Giúp mk với:
Tính:
\(D=\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)
tính
\(\sqrt{28-10\sqrt{3}}\)
\(\sqrt{41+12\sqrt{5}}\)
\(\sqrt{32-10\sqrt{7}}\)
\(\sqrt{11-4\sqrt{7}}\)
THỰC HIỆN PHÉP TÍNH
1,\(\sqrt{3+\sqrt{5}}.\sqrt{2}\)
2,\(\sqrt{3-\sqrt{5}.\sqrt{8}}\)
3,\((\sqrt{\dfrac{3}{4}}-\sqrt{3}+5\sqrt{\dfrac{4}{3})}.\sqrt{12}\)
4,\((\sqrt{\dfrac{1}{7}}-\sqrt{\dfrac{16}{7}}+\sqrt{7}):\sqrt{7}\)
5, \(\sqrt{36-12\sqrt{5}}:\sqrt{6}\)
6,\(\sqrt{3-\sqrt{5}:}\sqrt{2}\)
thực hiện phép tính
a)\(3\sqrt{9-\sqrt{25}+2\sqrt{49}}\)
b)\(7\sqrt[3]{27}-\sqrt[3]{64}+2\sqrt[3]{8}\)
c)\(\left(\sqrt{28}+2\sqrt{14}+3\sqrt{7}\right)\left(\sqrt{7}-7\sqrt{8}\right)\)
d)\(\frac{6\sqrt{7}+\sqrt{12}}{2}+\sqrt{7}+\sqrt{67-12\sqrt{7}}\)
\(\sqrt{12-3\sqrt{7}}-\sqrt{12\text{+}3\sqrt{7}}\)
Tính
G.\(\sqrt{7-2\sqrt{6}}\)
H.\(\sqrt{13-4\sqrt{3}}\)
I. \(\sqrt{7-4\sqrt{3}}\)\(-2\)
J.\(\sqrt{15-6\sqrt{6}}\)+\(\sqrt{33-12\sqrt{6}}\)
\(A=\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)
\(B=\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)\(C=\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\)
Thực hiện các phép tính sau:
a, A=\(\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)
b, B=\(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
c, C=\(\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\)