g: \(=\left|\sqrt{6}-1\right|=\sqrt{6}-1\)
h: \(=\left|2\sqrt{3}-1\right|=2\sqrt{3}-1\)
l: \(=\left|2-\sqrt{3}\right|-2=2-\sqrt{3}-2=-\sqrt{3}\)
j: \(=\left|3-\sqrt{6}\right|+\left|2\sqrt{6}-3\right|\)
\(=3-\sqrt{6}+2\sqrt{6}-3=\sqrt{6}\)
g: \(=\left|\sqrt{6}-1\right|=\sqrt{6}-1\)
h: \(=\left|2\sqrt{3}-1\right|=2\sqrt{3}-1\)
l: \(=\left|2-\sqrt{3}\right|-2=2-\sqrt{3}-2=-\sqrt{3}\)
j: \(=\left|3-\sqrt{6}\right|+\left|2\sqrt{6}-3\right|\)
\(=3-\sqrt{6}+2\sqrt{6}-3=\sqrt{6}\)
Tính:
1) \(\sqrt{14-2\sqrt{33}}\)
2) \(\sqrt{12-2\sqrt{35}}\)
3) \(\sqrt{16-2\sqrt{55}}\)
4) \(\sqrt{14-6\sqrt{5}}\)
5) \(\sqrt{17-12\sqrt{2}}\)
6) \(\sqrt{27-12\sqrt{5}}\)
7) \(\sqrt{4+\sqrt{15}}\)
LÀM CHI TIẾT GIÚP MK NHÉ!
Thực hiện phép tính
a) \(\left(2-\sqrt{3}\right)^2-\sqrt{4-2\sqrt{3}}+\sqrt{12}\)
b)\(\frac{2\sqrt{12}-\sqrt{6}}{2\sqrt{6}-\sqrt{3}}+\frac{10+\sqrt{5}}{2\sqrt{15}+\sqrt{3}}\)
c)\(\left(\frac{3+2\sqrt{3}}{\sqrt{3}+2}+\frac{2+\sqrt{2}}{\sqrt{2}+1}\right):\left(\sqrt{2}+\sqrt{3}\right)\)
d)\(\sqrt{10-4\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
e)\(\sqrt{16-6\sqrt{7}}+\sqrt{32-8\sqrt{7}}\)
f)\(\sqrt{28-16\sqrt{3}}+\sqrt{73-40\sqrt{3}}\)
a : \(\sqrt{3-2\sqrt{2}}+\sqrt{\left(2-\sqrt{2}\right)^2}\)
b : \(\sqrt{33-12\sqrt{6}}-\sqrt{\left(5-2\sqrt{6}\right)^2}\)
c : \(\sqrt{7-2\sqrt{6}}+\sqrt{15-6\sqrt{6}}\)
Rút gọn biểu thức:
C =\(\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
D = \(\sqrt{2-\sqrt{3}}-\sqrt{2+\sqrt{3}}\)
E = \(\sqrt{3+\sqrt{5}}+\sqrt{7-3\sqrt{5}}-\sqrt{2}\)
G = \(\sqrt{x+2\sqrt{2x-4}+\sqrt{x-2\sqrt{2x-4}}}\)với x \(\ge\)2
1. Tính:
a) \(\frac{\sqrt{7}-5}{2}-\frac{6-2\sqrt{7}}{4}+\frac{6}{\sqrt{7}-2}-\frac{5}{4+\sqrt{7}}\)
b) \(\frac{2}{\sqrt{6}-2}+\frac{2}{\sqrt{6}+2}+\frac{5}{\sqrt{6}}\)
c) \(\frac{1}{\sqrt{3}}+\frac{1}{3\sqrt{2}}+\frac{1}{\sqrt{3}}\sqrt{\frac{5}{12}-\frac{1}{\sqrt{6}}}\)
d) \(\frac{2\sqrt{3-\sqrt{3+\sqrt{13+\sqrt{48}}}}}{\sqrt{6}-\sqrt{2}}\)
Tính:
1) \(\sqrt{4-2\sqrt{3}}\)
2) \(\sqrt{5+2\sqrt{6}}\)
3) \(\sqrt{7-2\sqrt{10}}\)
4) \(\sqrt{14-6\sqrt{6}}\)
5) \(\sqrt{8+2\sqrt{15}}\)
6) \(\sqrt{10-2\sqrt{21}}\)
7) \(\sqrt{11+2\sqrt{18}}\)
LÀM CHI TIẾT GIÚP MK NHÉ!
Biến đổi biểu thức trong căn thành bình phương 1 tổng hay 1 hiệu rồi từ đó phá bớt 1 lớp căn:
a)\(\sqrt{4-\sqrt{15}}\)
b) \(\sqrt{7-\sqrt{33}}\)
c) \(\sqrt{10-2\sqrt{6}+2\sqrt{10}-2\sqrt{15}}\)
d) \(\sqrt{25+4\sqrt{10}+4\sqrt{15}+4\sqrt{6}}\)
e) \(\sqrt{49-5\sqrt{96}}+\sqrt{49+5\sqrt{96}}\)
f) \(\sqrt{13-\sqrt{160}}-\sqrt{53+4\sqrt{90}}\)
g) \(\left(\sqrt{2}-3\right)\sqrt{11+6\sqrt{2}}\)
h) \(\left(3\sqrt{2}+\sqrt{10}\right)\sqrt{38-12\sqrt{5}}\)
Giúp tớ với ạ! Càng nhanh càng tốt nha! :))
Tính
A= \(\sqrt{\left(1-\sqrt{3}\right)^2}-\sqrt{\left(\sqrt{3}+2\right)^2}\)
B=\(\sqrt{\left(2-\sqrt{3}\right)^2}+\sqrt{4-2\sqrt{3}}\)
C=\(\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
Phân tích :
1) \(\sqrt{29+12\sqrt{5}}\) - \(\sqrt{29-12\sqrt{5}}\)
2) \(\sqrt{8-2\sqrt{15}}\)- \(\sqrt{23-4\sqrt{15}}\)
3) \(\sqrt{8-2\sqrt{15}}\) + \(\sqrt{48+6\sqrt{15}}\)
4) \(\sqrt{49-5\sqrt{96}}\)+\(\sqrt{49+5\sqrt{96}}\)
5) \(\sqrt{15-6\sqrt{15}}\)+\(\sqrt{33-12\sqrt{6}}\)
6) \(\sqrt{16-6\sqrt{7}}\)+\(\sqrt{64-24\sqrt{7}}\)
7) \(\sqrt{14-6\sqrt{5}}\)+\(\sqrt{14+6\sqrt{5}}\)
8) \(\sqrt{1-6\sqrt{2}}\)+\(\sqrt{11-6\sqrt{2}}\)
9) \(\sqrt{13+4\sqrt{10}}\)+\(\sqrt{13-4\sqrt{10}}\)
10) \(\sqrt{46-6\sqrt{5}}\)+\(\sqrt{29-12\sqrt{5}}\)